Click here👆to get an answer to your question ️ Rationalise the denominator √(3)√(2)√(3)√(2)Sin 15° = (1 / √2) (√3 / 2) ( 1/ √2) (1 / 2) = √3 / 2√2 1 / 2√2 = (√3 1) / 2√2 Answer sin 15° = (√3 1) / 2√2 Example 2 Find the exact value of cot 15° Solution To find The value of cot 15° Using one of the angle difference formulas (of tan), tan (A B) = (tan A tan B) / (1 tan A tan B)= cos(600 450 ) = cos 600 cos 450 – sin 600 sin 450 = – √3 /2 X 1 /√2½ X 1 /√2 = 1 2√2 – √3 2√2 = 1 – √3 2√2 Key Question 2 18
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1.rationalise the denominator of (3-sqrt(2))/(3+sqrt(2))
1.rationalise the denominator of (3-sqrt(2))/(3+sqrt(2))-Rationalise the Denominator of 1/ √3 √2 1 CISCE ICSE Class 9 Question Papers 10 Textbook Solutions Important Solutions 5 Question Bank Solutions Concept Notes & Videos 261 Syllabus Advertisement Remove all ads Rationalise the Denominator of 1/ √3 √2 1 MathematicsSin 15° = (√3/2√2)(1/2√2) Sin 15° = (√3–1)/2√2 Value of Sin 15 in Decimal Since, we know, Sin 15° = (√3–1)/2√2 Let us rationalise the denominator on the Righthand side of the above expression ⇒ (√3–1)/2√2 Multiply and divide √2 ⇒ (√3–1)/2√2 x (√2/√2) ⇒
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Formula sin 2 θ cos 2 θ = 1 1 sin 2 θ = cos 2 θ 1 cos 2 θ = sin 2 θ Move sin 2 θ or cos 2 θ to the right side tan 2 θ 1 = sec 2 θ 1 cot 2 θ = csc 2 θ ÷ sin 2 θ or cos 2 θ both sides=1/√2√3/21/√21/2 sin45°=cos45°=1/√2 =√31/2√2 Ans Cos15°=cos(45°–30°) => Cos(AB)=cosAcosBsinAsinB Cos(45°30°)=cos45°cos30°sin45°sin30° =1/√2 √3/21/√2 1/2 sin30°=1/2 & cos30°=√3/2 =√3/2√21/2√2 =√31/2√2 Ans👍 Correct answer the question Rationalise the denominator √3−1 /2√2√3 ianswersincom
4 f(x h)−f(x)/h plug x h instead of x f(xh)=2(hx) 2 −5(hx)4 2(hx) 2 −5(hx)4) – (2x 2 – 5x 4)/h = 2h 4x 5 Q (8), a 4x – 2y = 3James Yates , Masters Mathematics, University of Oxford (01) Answered to rationalise a denominator of this type, (ignoring for a moment the 2s cancel) a) Multiply top and (If √ xy were rational, then √ a² b would have been rational and you wouldn't have any nested radicals to begin with) The rational parts are equal 2 = x y Solve that simultaneously with the equation x − y = 1 that we developed a couple of steps back, and you get x = 3/2, y = 1/2 ⇒ √ 2 √3 = √ 3/2 √ 1/2
= (√3 1)/2√2 / {2 √2 (√3 1) /2√2} = (√3 1) / 2 √2 (√3 1) Multiply both numerator and denominator by 2 √2 (√31) = (√3 1) 2 √2 (√3 1) / 4(2) (√3 1) 2 = (√3 1)2√2 √3 1 / 4(2) (√3 1) 2 = (2√6 3 √3 2 √2 √3 1) / 8 (3 1 2 √3)Rationalising the denominator of three terms Rationalise 1/√2√3√5#class9maths #class9mathsimportantquestions #chapter1extraquestionsclass9 #extraquestion= √3/2 × 1/√2 1/2 × 1/√2 = √3/2√2 1/2√2 = (√31)/2√2 Example 3 A boy sees a bird sitting on a tree at an angle of elevation of ° If a boy is standing 10
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√= 3 × 6 3 × 4√2 6 3 4√2 × √3 So we get √ = 18 12 2 6√3 4√6 6 Solution (i) (5 √5) (5 5) According to the formula 2− 2=( )( − ) = (5)2 √– ( 5)2 So we get = 25 – 5 = √Hence (5 √5) (5 5) is rational (ii) (√32) 2 According to the formula ( )2= 2 22 Rationalise the denominator of each of the following (i) 3√5 (ii) 3/2√5 (iii) 1/√12 (iv) √2/√5 asked Apr 15 in Number System by Madhuwant ( 381k points) rationalisation) = 2 ?
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Exact value of cos 1050 ?Now we can write 4 2√3 as (1 √3)^2 as we discussed above √ (√3 31 √3) √3 ( square will cancel the square root and only 1√3 will be left) √ (2√3 4) √3 Now again we can write 4 2√3 as (1√3)^2 1 √3 √3=1 ( again square and square root gets cancelled) So here's your answer Hope this helps Rationalise the denominator of each of the following (i) 3√5 (ii) 3/2√5 (iii) 1/√12 (iv) √2/√5 asked Apr 15 in Number System by Madhuwant ( 381k points) rationalisation
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2 − 5 ?(1/√2) * (√3/2) (1/√2) * ½ (√31)/ 2√2 = (√3 1)(√2)/4 = (√2√6)/4 (√2√6)/4 Q (6) Difference quotient for 푓 (?
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